A = [ * 20 c 0&3 2&0 ]and A^ - 1 = (adj(A)),then = - Vidyadip

MCQ

$A = \left[ {\begin{array}{*{20}{c}}0&3\\2&0\end{array}} \right]$and ${A^{ - 1}} = \lambda (adj(A)),$then $\lambda = $

✓
$\frac{{ - 1}}{6}$
B
$\frac{1}{3}$
C
$\frac{{ - 1}}{3}$
D
$\frac{1}{6}$

✓

Answer

Correct option: A.

$\frac{{ - 1}}{6}$

a
(a)$K = {[|A|]^{ - 1}} = \frac{{ - 1}}{6}$.

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