MCQ
A light has amplitude $A$ and angle between analyser and polariser is $60^{\circ}$. Light is reflected by analyser has amplitude
- A$A \sqrt{2}$
- B$A / \sqrt{2}$
- C$\sqrt{3} A / 2$
- ✓$A / 2$
✓
Answer
Correct option: D.
$A / 2$
The amplitude will be $A \cos 60^{\circ}=A / 2$
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