Question
A light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^o $. If the shaded half of the prism is knocked off, the ray will

Answer

(c) By formula $\delta = (n - 1)A \Rightarrow 34 = (n - 1)A$ and in the second position $\delta ' = (n - 1)\frac{A}{2}$
$\therefore $ $\frac{{34}}{{\delta '}} = \frac{{(n - 1)A}}{{(n - 1)\frac{A}{2}}}$ or $\delta ' = \frac{{34}}{2} = {17^o}$

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