MCQ
A light ray is incident upon a prism in minimum deviation position and suffers a deviation of $34^{\circ}$. If the shaded half of the prism is knocked off, the ray will
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  • A
    Suffer a deviation of $34^{\circ}$
  • B
    Suffer a deviation of $68^{\circ}$
  • Suffer a deviation of $17^{\circ}$
  • D
    Not come out of the prism

Answer

Correct option: C.
Suffer a deviation of $17^{\circ}$
By formula $\delta=(n-1) A \Rightarrow 34=(n-1) A$ and in the second position $\delta^{\prime}=(n-1) \frac{A}{2}$
$\therefore \frac{34}{\delta^{\prime}}=\frac{(n-1) A}{(n-1) \frac{A}{2}} \text { or } \delta^{\prime}=\frac{34}{2}=17^{\circ}$

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