MCQ
The average power dissipation in a pure capacitance in ac circuit is
- A$\frac{1}{2} C V^2$
- B$C V^2$
- C$\frac{1}{4} C V^2$
- ✓$0$
✓
Answer
Correct option: D.
$0$
Average power in ac circuits is given by $P=V_{r m s} i_{r m s} \cos \phi$
For pure capacitive circuit $\phi=90^{\circ}$ so $P=0$
For pure capacitive circuit $\phi=90^{\circ}$ so $P=0$
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