MCQ
A line $AB$ makes zero intercepts on $x$-axis and $y$-axis and it is perpendicular to another line $CD$, $3x + 4y + 6 = 0.$ The equation of line $ AB$ is
- A$y = 4$
- B$4x - 3y + 8 = 0$
- ✓$4x - 3y = 0$
- D$4x - 3y + 6 = 0$
We also know that slope of the given line $CD = - \frac{a}{b} = \frac{{ - 3}}{4}.$ Since the line $AB$ is perpendicular to the line $CD$, therefore slope of the line $AB(m) = \frac{4}{3}$. Thus relation for the equation of the line $AB$ will be $(y - {y_1}) = m(x - {x_1})$ or $y - 0 = \frac{4}{3}(x - 0)$ or $3y = 4x$ or $4x - 3y = 0$.
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