MCQ
A line joining points $(4,-1,2)$ and $(-3,2,3)$ meets a plane perpendicularly at point $(-10,5,4)$. Equation of this plane is
  • A
    $7 x-3 y+z+89=0$
  • $7 x-3 y-z+89=0$
  • C
    $7 x+3 y+z+89=0$
  • D
    $7 x-y+3 z=89$

Answer

Correct option: B.
$7 x-3 y-z+89=0$
(B)
The plane passes through $(-10,5,4)$
This point satisfies the equation of plane in option (B)
Also, it has d.r.s. $7,-3,-1$
$\therefore \quad$ option (B) is correct answer.

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