- A3
- B$\sqrt{2}$
- C$\sqrt{3}$
- D2
(c) : Since, line makes equal angles with coordinate axes, so direction cosine of line are $\frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}, \frac{1}{\sqrt{3}}$ Any point $Q$ on the line at a distance $t$ from $P(2,-1,2)$ is given by $\left(2+\frac{t}{\sqrt{3}},-1+\frac{t}{\sqrt{3}}, 2+\frac{t}{\sqrt{3}}\right)$
This point $Q$ meets the plane $2 x+y+z=9$.
$\begin{aligned}
& \Rightarrow 2\left(2+\frac{t}{\sqrt{3}}\right)+\left(-1+\frac{t}{\sqrt{3}}\right)+\left(2+\frac{t}{\sqrt{3}}\right)=9 \\
& \Rightarrow 4+\frac{2 t}{\sqrt{3}}-1+\frac{t}{\sqrt{3}}+2+\frac{t}{\sqrt{3}}=9 \Rightarrow 5+\frac{4 t}{\sqrt{3}}=9 \\
& \Rightarrow \frac{t}{\sqrt{3}}=1 \Rightarrow t=\sqrt{3}
\end{aligned}$
$\therefore \quad$ Distance between $P$ and $Q$ is $\sqrt{3}$
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