MCQ
A liquid drop of diameter $D$ breaks into $27$ tiny drops. The change in energy is
- ✓$2\pi \,TD^2$
- B$4\pi \,TD^2$
- C$\pi \,TD^2$
- DNone of these
✓
Answer
Correct option: A.
$2\pi \,TD^2$
a
$\Delta SE = 4\pi R^2T\,\,(n^{1/3}-1)$
$\Delta SE = 4\pi R^2T\,\,(n^{1/3}-1)$
$= 4\pi \frac {D^2}{4}T [(27)^{1/3}-1] = 2\pi D^2T$
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