A liquid flows in a tube from left to right as shown in figure. ${A_1}$ and ${A_2}$ are the cross-sections of the portions of the tube as shown. Then the ratio of speeds ${v_1}/{v_2}$ will be
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(b) $\overrightarrow {\frac{{\Delta v}}{{\Delta t}}} = \frac{{{A_1}{v_1}\Delta t}}{{\Delta t}} = \frac{{\overrightarrow {\Delta v} }}{{\Delta t}} = \frac{{{A_2}{v_2}\Delta t}}{{\Delta t}}$
${A_1}{v_1} = {A_2}{v_2}$
${A_1}{v_1} = {A_2}{v_2}$
${A_1}{v_1} \subset {A_2}{v_2}$
$A_2/A_1$
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