Two persons pull a wire towards themselves. Each person exerts a force of $200 \mathrm{~N}$ on the wire. Young's modulus of the material of wire is $1 \times 10^{11} \mathrm{~N} \mathrm{~m}^{-2}$. Original length of the wire is $2 \mathrm{~m}$ and the area of cross section is $2 \mathrm{~cm}^2$. The wire will extend in length by . . . . . . . .$\mu \mathrm{m}$.
A$17$
B$18$
C$20$
D$21$
JEE MAIN 2024, Diffcult
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C$20$
c $\frac{\mathrm{F}}{\mathrm{A}}=\mathrm{Y} \frac{\Delta \ell}{\ell} \Rightarrow \Delta \ell=\frac{\mathrm{F} \ell}{\mathrm{AY}}$
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