MCQ
A long conducting wire having a current $I$ flowing through it, is bent into a circular coil of $N$ turns.Then it is bent into a circular coil of $n$ tums. The magnetic field is calculated at the centre of coils in both the cases. The ratio of the magnetic field in first case to that of second case is:
  • A
    $N : n$
  • B
    $n^2: N^2$
  • $N ^2: n ^2$
  • D
    $n: N$

Answer

Correct option: C.
$N ^2: n ^2$
c

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