A long copper tube of inner radius $R$ carries a current $i$. The magnetic field $B$ inside the tube is
A$\frac{{{\mu _0}i}}{{2\pi R}}$
B$\frac{{{\mu _0}i}}{{4\pi R}}$
C$\frac{{{\mu _0}i}}{{2R}}$
D
Zero
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D
Zero
d (d) Magnetic field inside the hollow conductor (tube) is zero.
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A wire carrying current $I$ has the shape as shown in adjoining figure.Linear parts of the wire are very long and parallel to $X-$axis while semicircular portion of radius $R$ is lying in $Y-Z$ plane. Magnetic field at point $O$ is
Assertion : Free electrons always keep on moving in a conductor even then no magnetic force act on them in magnetic field unless a current is passed through it.
Reason : The average velocity of free electron is zero.