A straight wire carrying a current $10\, A$ is bent into a semicircular arc of radius $5\, cm.$ The magnitude of magnetic field at the center is
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(c) $B = \frac{{{\mu _0}}}{{4\pi }} \times \frac{{\pi i}}{r} \Rightarrow B = {10^{ - 7}} \times \frac{{\pi \times 10}}{{5 \times {{10}^{ - 2}}}} = 6.28 \times {10^{ - 5}}\,T$
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