A long solenoid has $200$ turns per cm and carries a current of $2.5\, amps$. The magnetic field at its centre is $({\mu _0} = 4\pi \times {10^{ - 7}}\,weber/amp{\rm{ - }}m)$
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(b) $B = {\mu _0}ni = 4\pi \times {10^{ - 7}} \times \frac{{200}}{{{{10}^{ - 2}}}} \times 2.5$$ = 6.28 \times {10^{ - 2}}\,Wb/{m^2}$
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