MCQ
A magnet when placed perpendicular to a uniform field of strength $10^{-4} \mathrm{~Wb} / \mathrm{m}^2$ experiences a maximum couple of moment $4 \times 10^{-5} \mathrm{~N} / \mathrm{m}$. What is its magnetic momen
  • $0.4\ \mathrm{A} \times \mathrm{m}^2$
  • B
    $0.2\  \mathrm{A} \times \mathrm{m}^2$
  • C
    $0.6\ \mathrm{A} \times \mathrm{m}^2$
  • D
    $0.04\  \mathrm{A} \times \mathrm{m}^2$

Answer

Correct option: A.
$0.4\ \mathrm{A} \times \mathrm{m}^2$
(a) $0.4\ \mathrm{A} \times \mathrm{m}^2$

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