A man measures the period of a simple pendulum inside a stationary lift and finds it to be $T$ sec. If the lift accelerates upwards with an acceleration $\frac{g}{4}$, then the period of the pendulum will be
  • A$T$
  • B$\frac{T}{4}$
  • C$\frac{{2T}}{{\sqrt 5 }}$
  • D$2T\sqrt 5 $
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