Question
Two simple harmonic motions are represented by equations ${y_1} = 4\,\sin \,\left( {10t + \phi } \right)$ and ${y_2} = 5\,\cos \,10\,t$ What is the phase difference between their velocities?
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Answer
$y_{1}=4 \sin (10 t+\phi)$
$y_{2}=5 \cos 10 t$
$\Rightarrow \mathrm{y}_{2}=5 \sin \left(10 \mathrm{t}+\frac{\pi}{2}\right)$
phase difference $\frac{\pi}{2}-\phi$
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