A man stands between two high rise buildings and blows a whistle.…

MCQ

A man stands between two high rise buildings and blows a whistle. He hears two successive echoes one after 0.4 second other after 1.6 second. Calculate the distance between the two buildings.[given velocity of sound in air $=332$ ms ${ }^{-1}$ ]

A
320 m
✓
332 m
C
340 m
D
350 m

✓

Answer

Correct option: B.

332 m

(b)
332 m
Explanation:
Wave velocity $=\frac{2 \times \text { Distance }}{\text { Time }}$
Given, $t_1=0.4 sec , t_2=1.6 sec , v=332 ms^{-1}$.
$
\begin{array}{l}
\therefore 332=\frac{2 \times d_1}{t_1} \\
332=\frac{2 d_1}{0.4} \Rightarrow d_1=66.4 m \\
\text { and } 332=\frac{2 \times d_2}{t_2} \\
332=\frac{2 d_2}{1.6} \\
\Rightarrow d_2=265.6 m
\end{array}
$
Therefore, total distance
$
\begin{array}{l}
=d_1+d_2 \\
=66.4+265.6=332 m
\end{array}
$

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