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44 questions · timed · auto-graded

MCQ 11 Mark
The minimum distance between the source and the reflector in air. So that an echo is heard is approximately equal to:
  • A
    10 m
  • 17 m
  • C
    34 m
  • D
    50 m
Answer
Correct option: B.
17 m
17 m

Explanation: An echo is heard distinctly if it reaches the ear at least 0.1 s after the original sound.
If d is the distance between the observer and the obstacle and V is the speed of sound, then the total distance travelled by the sound to reach the obstacle and then to come back is 2d and the time taken is,
t = Total distance travelled/Speed of sound = 2d/V
or, d = V t/2
Putting t = 0.1 s and V = 340 m/s in air at ordinary temperature, we get:
d = (340 x 0.1)/2 = 17 m
Thus, to hear an echo distinctly, the minimum distance between the source and the reflector in air is 17 m.

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MCQ 21 Mark
Which of the following graph shows the ideal condition for natural vibration.

  • Image
  • B

    Image

  • C

    Image

  • D

    Image

Answer
Correct option: A.

Image
(a)
Explanation:
In ideal conditions, the body vibrates with the same amplitude and frequency forever.
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MCQ 31 Mark
Bats detect obstacles in their path by producing:
  • A
    Infrasonic waves
  • Ultrasonic waves
  • C
    Electromagnetic waves
  • D
    Radio waves
Answer
Correct option: B.
Ultrasonic waves
(b)
Ultrasonic waves
Explanation:
Bats emit ultrasonic waves, which are sound waves with frequencies higher than 20 kHz, well above the human audible range, to navigate and locate objects through echolocation.
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MCQ 41 Mark
For effective reflection of sound waves, the condition of the surface should be:
  • A
    The surface must be smooth
  • B
    The surface must be polished
  • The reflecting surface must be larger than the wavelength of the sound wave
  • D
    The reflecting surface must be smaller than the wavelength of the sound wave
Answer
Correct option: C.
The reflecting surface must be larger than the wavelength of the sound wave
(c)
The reflecting surface must be larger than the wavelength of the sound wave
Explanation:
Sound waves reflect effectively off surfaces that are larger than their wavelength. When the reflecting surface is too small, the sound tends to diffract rather than reflect.
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MCQ 51 Mark
As the temperature of a gas increases, the speed of sound:
  • A
    Decreases
  • Increases
  • C
    Remains the same
  • D
    Cannot say
Answer
Correct option: B.
Increases
(b) Increases
Explanation:
The speed of sound in a gas increases with temperature because higher temperatures reduce the gas's density, allowing sound waves to travel faster.
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MCQ 61 Mark
During the vibration of medium particles, energy transformation occurs between:
  • A
    Heat energy to kinetic energy and vice versa
  • Kinetic energy to potential energy and vice versa
  • C
    Heat energy to potential energy and vice versa
  • D
    Potential energy to nuclear energy and vice versa
Answer
Correct option: B.
Kinetic energy to potential energy and vice versa
(b)
Kinetic energy to potential energy and vice versa
Explanation:
When particles of the medium vibrate, they alternately convert kinetic energy (motion) into potential energy (position) and back, facilitating the propagation of the wave.
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MCQ 71 Mark
The categories of mechanical waves include:
  • A
    Electrottnagnetic, longitudinal, transverse
  • B
    Electromagnetic, transverse
  • Longitudinal, transverse
  • D
    Electromagnetic, transverse
Answer
Correct option: C.
Longitudinal, transverse
(c)
Longitudinal, transverse
Explanation:
Mechanical waves are classified into two main types: longitudinal waves, where particle displacement is parallel to wave motion, and transverse waves, where particle displacement is perpendicular to wave motion.
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MCQ 81 Mark
When the stem of vibrating tuning fork is pressed on a table, the tabletop starts Vibrating. These vibrations are definitely an example of:
  • A
    resonance
  • B
    natural vibrations
  • forced vibrations
  • D
    damped vibrations
Answer
Correct option: C.
forced vibrations
(c) forced vibrations
Explanation:
This is because the tuning fork forces the tabletop to vibrate at its own frequency.
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MCQ 91 Mark
Two sound waves X and Y have same amplitude and same wave pattern, but their frequencies are 60 Hz and 120 Hz respectively, then:
  • A
    X will be shriller and Y will be grave
  • X will be grave and Y will be shriller
  • C
    X will differ in quality than Y
  • D
    X is louder than Y
Answer
Correct option: B.
X will be grave and Y will be shriller
(b)
X will be grave and Y will be shriller
Explanation:
Greater the frequency more would be the shrillness.
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MCQ 101 Mark
Two notes are produced from two different musical instruments, such that they have same loudness and same pitch. The produced notes differ in their:
  • Waveform
  • B
    Frequency
  • C
    Wavelength
  • D
    Speed
Answer
Correct option: A.
Waveform
(a)
Waveform
Explanation:
Musical characteristic identified due to different sources is called waveform
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MCQ 111 Mark
When a body vibrates under a periodic force, the vibrations of the body are always:
  • A
    natural vibrations
  • B
    damped vibrations
  • forced vibrations
  • D
    resonant vibrations
Answer
Correct option: C.
forced vibrations
(c)
forced vibrations
Explanation:
When a body vibrates under a periodic force the vibrations of the body are forced vibrations, as they are driven by an external force.
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MCQ 121 Mark
The ratio of the wavelength of A: wavelength of B is __________ .
Image
  • A
    5:2
  • 1:2
  • C
    2:1
  • D
    2:3
Answer
Correct option: B.
1:2
(b)
$1: 2$
Explanation:
$\frac{\text { The frequency of } A }{\text { The frequency of } B }=\frac{2}{1}$
and wavelength $(\lambda) \propto \frac{1}{\text { frequency }(f)}$
Hence, the ratio of the wavelength of A and that of B is $1: 2$.
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MCQ 131 Mark
What is referred as 'Shrill'?
  • A
    Sound with low intensity
  • Sound with high frequency
  • C
    Sound with low amplitude
  • D
    None of the above
Answer
Correct option: B.
Sound with high frequency
(b)
Sound with high frequency
Explanation:
Pitch is the feature of sound that distinguishes an acute (or shrill) noise from a grave or flat tone. Sound with high frequency also known as Shrill.
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MCQ 141 Mark
If the amplitude of a wave is halved, what will be the effect on its loudness?
  • $1 / 4$ times
  • B
    $1 / 2$ times
  • C
    will remain constant
  • D
    2 times.
Answer
Correct option: A.
$1 / 4$ times
(a)
1/4 times
Explanation:
The relation between loudness and amplitude is loudness $\propto$ (Amplitude) $^2$. So, if the amplitude of a wave is halved, its loudness will become $1 / 4$ times.
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MCQ 151 Mark
How a blind person recognizes a person?
  • Unique waveform of vocal cord of an individual
  • B
    Unique loudness of an individual
  • C
    Unique amplitude of sound of an individual
  • D
    All of the above
Answer
Correct option: A.
Unique waveform of vocal cord of an individual
(a)
Unique waveform of vocal cord of an individual
Explanation:
Every individual have their unique waveform of vocal cord. By that we can identify any person without seeing him/her.
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MCQ 161 Mark
Match the following:
Column IColumn II
I. Permanent damage to the ears(i) Greater than 120 dB
II. Safe limit of level of sound(ii) 0-80 dB
III. Soothing sensation(iii) 10-30 dB
IV. Lowest level of loudness(iv) 0 dB
  • 1-(і), ll-(ін), Ш-(ii), IV-(iv)
  • B
    1-(i), II-(ii), III-(iv), IV-(iii)
  • C
    I (iii), II (i), III (ii), IV (iv)
  • D
    I-(iii), I-(ii), Ⅲ-(iv), TV-(1)
Answer
Correct option: A.
1-(і), ll-(ін), Ш-(ii), IV-(iv)
(a)
l-(i), II-(ii), III-(iii), IV-(iv)
Explanation:
Lowest level of loudness is 0 dB, which a man can hear. Approximately, sound in the range of 0-80 dB is categorised as safe limit of level of sound, Sound of level 10 dB to 30 dB has a soothing sensation. Sound of greater than 120 dB can
potentially damage the ears of listerner.

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MCQ 171 Mark
A 'hearing aid' is device that:
  • A
    Converts nuclear energy to sound waves.
  • Converts sound waves to electrical signals, which are subsequently amplified before being converted back to sound waves.
  • C
    Convert sound waves to mechanical waves.
  • D
    None of the above
Answer
Correct option: B.
Converts sound waves to electrical signals, which are subsequently amplified before being converted back to sound waves.
(b)
Converts sound waves to electrical signals, which are subsequently amplified before being converted back to sound waves.
Explanation:
Hearing aid is an electronic device used by people with hearing loss. It first converts sound waves to electrical signals, which are subsequently amplified by an amplifier before being converted back to clear and louder sound waves.
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MCQ 181 Mark
Arrange the following in ascending order in terms of levels of sound?
l. Music recording studio
II. Heavy traffiu
III. Flying jet aircraft
  • I-II-III
  • B
    II-III-I
  • C
    III-I-II
  • D
    I-III-II
Answer
Correct option: A.
I-II-III
(a) I-II-III
Explanation:
To minimize the disturbances and clear recording, the noise level or sound level in a music recording studio should be kept to a minimum. Jet aircraft make substantially more noise and a lot larger sound wave than heavy traffic. As a result, the correct order is (a).
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MCQ 191 Mark
The ratio of the wavelength to waves is 4: 5. The ratio of their frequency is __________ :
(If the velocity of the waves are same)
  • A
    4:5
  • 5:4
  • C
    3:2
  • D
    none of these
Answer
Correct option: B.
5:4
(b) 5:4
Explanation:
$
\begin{array}{l}
\frac{f_{A}}{f_{B}}=\frac{\lambda_{B}}{\lambda_{A}} \\
\frac{f_{B}}{f_{A}}=\frac{\lambda_{A}}{\lambda_{B}} \\
\frac{f_{B}}{f_{A}}=\frac{4}{5}
\end{array}
$
$
\therefore f_{A}: f_{B}=5: 4
$
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MCQ 201 Mark
The frequency at which the sound of vibration of the pendulum is not audible is:
  • Less than 20 Hz
  • B
    More than 20 Hz
  • C
    20 Hz
  • D
    None of the above
Answer
Correct option: A.
Less than 20 Hz
(a)
Less than 20 Hz
Explanation:
Human hearing typically ranges from 20 Hz to 20,000 Hz. Frequencies below 20 Hz are considered infrasonic and are not audible to the human ear. Therefore, if a pendulum vibrates at a frequency low than 20 Hz, its sound would not be audible.
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MCQ 211 Mark
Vibration which take place under the influence of an external periodic force ____________ :
  • A
    Damped vibration
  • Forced vibration
  • C
    Free vibration
  • D
    Natural vibration
Answer
Correct option: B.
Forced vibration
(b)
Forced vibration
Explanation:
In forced vibration, the vibrations of the body takes place under the influence of an external periodic force acting on it.
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MCQ 221 Mark
A cord stretched among the 2 constant supports, is plucked precisely within side, the centre after which is released. It executes, which type of vibrations consider resistance of medium
  • A
    Resonant vibration
  • Damped vibration
  • C
    Forced vibration
  • D
    Natural vibration
Answer
Correct option: B.
Damped vibration
(b)
Damped vibration
Explanation:
Damped vibration, as due to resistance of the medium the amplitude will decrease with time and stop at the end.
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MCQ 231 Mark
Which of the following graph shows the condition for damped vibration.
  • A

    Image

  • Image
  • C

    Image
  • D

    Image
Answer
Correct option: B.

Image
(b)
Explanation:
In damped vibrations, the amplitude of the vibrating body continuously decreases with time and finally it stop vibrating.
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MCQ 241 Mark
What kind of vibration the picture depicts?
Image
  • A
    Forced
  • Free
  • C
    Damped
  • D
    Both (a) and (c).
Answer
Correct option: B.
Free
(b)
Free
Explanation:
In free vibrations the amplitude remains constant with time due to absence of any external resistive force. Thus, it is free vibration.
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MCQ 251 Mark
Which of the following is true for free vibration?
  • A
    External force is applied.
  • No external force is applied.
  • C
    It does not depend upon the shape and size of the body.
  • D
    All are correct.
Answer
Correct option: B.
No external force is applied.
(b)
No external force is applied.
Explanation:
Free vibrations are the vibrations of a body that occur in the absence of any external force and the vibration is determined by the body's form and size.
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MCQ 261 Mark
In the moon, when a bob of a simple pendulum of length 500 cm is displaced from its mean position (A), calculate natural frequency of pendulum in free vibration.
Image
  • A
    0.15 Hz
  • B
    0.12 Hz
  • 0.09 Hz
  • D
    0.06 Hz
Answer
Correct option: C.
0.09 Hz
(c)
0.09 Hz
Explanation:
Given, $l=500 cm=5 m$,
$\because$ Acceleration due to gravity on the moon is 6 times less than the acceleration due to gravity on earth.
$
\therefore g(\text { on moon })=\frac{9.81}{6}
$
None, $f=\frac{1}{2 \pi} \sqrt{\frac{8}{l}}$
$f=\frac{1}{2 \times 3.14} \times \sqrt{\frac{9.81}{6 \times 5}}$
$=\frac{1}{2 \times 3.14} \times \sqrt{0.327}$
$=\frac{1}{6.28} \times 0.571$
$f=0.09 Hz$.
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MCQ 271 Mark
Match the following:
Column IColumn II
(i) Light Wave1. Satellite signals
(ii) Sound Wave2. TV remote controls
(iii) Infrared rays3. Cannot travel in outer space
(iv) Radio waves4. Can travel in vacuum
  • A
    (i)-1, (ii)-3, (iii)-2, (iv)-4
  • B
    (i)-1, (ii)-2, (iii)-3, (iv)-4
  • (i)-4, (ii)-3, (iii)-2, (iv)-1
  • D
    (i)-4, (ii)-2, (iii)-3, (iv)-1
Answer
Correct option: C.
(i)-4, (ii)-3, (iii)-2, (iv)-1
(c)
(i)-4, (ii)-3, (iii)-2, (iv)-1
Explanation:
In a vacuum, light waves can travel. Sound wave cannot travel in space because it require a medium to propagate. Infrared rays are used in TV remote controls. Satellite communication is transmitted via radio waves.

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MCQ 281 Mark
Bats use this technique to detect their prey and hunt them...... .
Image
  • A
    flapping their wings
  • B
    echo
  • C
    reflection of sound waves
  • both (b) and (c)
Answer
Correct option: D.
both (b) and (c)
(d)
both (b) and (c)
Explanation:
Bats can produce and detect high frequency sound waves of about 100 kHz that does not lie in human audible range. These waves are used to locate obstacle at right. These sound waves strike any obstacle in their path and are reflected as echoes to the bat's ear.
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MCQ 291 Mark
Name the machine seen in the figure using the principle of echo.
Image
  • A
    sonography
  • B
    electro cardiogram
  • echo cardiogram
  • D
    intra venous machine
Answer
Correct option: C.
echo cardiogram
(c)
echo cardiogram
Explanation:
An echocardiogram checks how your how your heart's chamber and values are pumping blood through your heart.
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MCQ 301 Mark
A man stands in between two vertical cliffs $X$ and $Y$ such that he is at a distance of 660 m from $X$. When he explodes cracker, he hears the first echo after 4 second and second echo 6 second later. Calculate the speed of sound in air and the distance of cliff $Y$ from the man . . . .
  • $330 ms^{-1}, 1650 m$
  • B
    $320 ms^{-1}, 1400 m$
  • C
    $340 ms^{-1}, 1700 m$
  • D
    none of these.
Answer
Correct option: A.
$330 ms^{-1}, 1650 m$
(a)
$330 ms^{-1}, 1650 m$
Explanation:
Given, $t_1=4 sec , t_2=4+6=10 sec , d_1=660 m$
$\because$ Velocity $=\frac{2 \times \text { distance }}{\text { time }}$
$
\therefore v=\frac{2 \times d_1}{t_1} \Rightarrow v-\frac{2 \times 660}{4}
$
$
v=330 ms^{-1}
$
Now, $v=\frac{2 \times d_2}{t_2}$
$
\begin{array}{l}
300=\frac{2 \times d_2}{10} \\
d_2=330 \times 5=1650 m .
\end{array}
$
So, distance of diff. $Y$ from the man $=1650 m$.
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MCQ 311 Mark
A man stands between two high rise buildings and blows a whistle. He hears two successive echoes one after 0.4 second other after 1.6 second. Calculate the distance between the two buildings.[given velocity of sound in air $=332$ ms ${ }^{-1}$ ]
  • A
    320 m
  • 332 m
  • C
    340 m
  • D
    350 m
Answer
Correct option: B.
332 m
(b)
332 m
Explanation:
Wave velocity $=\frac{2 \times \text { Distance }}{\text { Time }}$
Given, $t_1=0.4 sec , t_2=1.6 sec , v=332 ms^{-1}$.
$
\begin{array}{l}
\therefore 332=\frac{2 \times d_1}{t_1} \\
332=\frac{2 d_1}{0.4} \Rightarrow d_1=66.4 m \\
\text { and } 332=\frac{2 \times d_2}{t_2} \\
332=\frac{2 d_2}{1.6} \\
\Rightarrow d_2=265.6 m
\end{array}
$
Therefore, total distance
$
\begin{array}{l}
=d_1+d_2 \\
=66.4+265.6=332 m
\end{array}
$
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MCQ 321 Mark
A person standing between two vertical cliffs hears two sounds one after 6 s and other 4 s later. The time for first echo is _________ and for second echo is _________ .
  • A
    $6 s, 4 s$
  • B
    $4 s, 6 s$
  • $6 s, 10 s$
  • D
    $10 s, 4 s$
Answer
Correct option: C.
$6 s, 10 s$
(c)
$6 s, 10 s$
Explanation:
Time for first echo is the shorter time and time for second echo is addition of first time with the second time.
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MCQ 331 Mark
A person standing in front of a vertical cliff whistles. He later moves towards the cliff by travelling a distance of 300 m at first, he hears the sound after 4 sec and then on travelling the distance he hears the echo after 9 sec . Time take for first echo is ___________ and time for the second echo is ________ .
  • $4 s, 5 s$
  • B
    $5 s, 4 s$
  • C
    $4 s, 9 s$
  • D
    $9 s, 4 s$
Answer
Correct option: A.
$4 s, 5 s$
(a)
$4 s, 5 s$
Explanation:
Time of first echo $=4$ seconds
Time of second echo $=9-4=5$ second
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MCQ 341 Mark
A person standing between two cliffs hears two echo one after 3 sec and another after 4 sec , so time taken for first echo is ______ and that for second echo is __________ .
  • A
    $3 s, 4 s$
  • $3 s, 1 s$
  • C
    $3 s, 7 s$
  • D
    $7 s, 7 s$
Answer
Correct option: B.
$3 s, 1 s$
(b)
$3 s, 1 s$
Explanation:
First echo is -3s
And the time taken for the second echo is -1s
The first echo arrives after 3 seconds, indicating a 3 -second round - trip time for the sound wave. The second echo arrives 1 second after the first, indicating a 1-second additional round-trip time to the second cliff.
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MCQ 351 Mark
Amphitheaters and auditorium walls are fitted with ________ to avoid the echoing of sound.
  • A
    granite
  • B
    Italian marble
  • sound absorbers such as foam board
  • D
    wooden wall
Answer
Correct option: C.
sound absorbers such as foam board
(c)
sound absorbers such as foam board
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MCQ 361 Mark
The repetition of sound heard in a cave or empty room is a case of __________ .
  • A
    echo
  • B
    superposition
  • C
    interpolation
  • reverberation
Answer
Correct option: D.
reverberation
(d)
reverberation
Explanation :
Reverberation is the phenomenon where sound wave inside on enclosed space persist due to repeated reflections from different surfaces.
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MCQ 371 Mark
The spread of a glacier in the arctic region can be judged by a submarine by using the principle of __________ .
  • A
    repetition of sound
  • reflection of sound
  • C
    refraction of sound
  • D
    none of the above
Answer
Correct option: B.
reflection of sound
(b)
reflection of sound
Explanation:
Submarines can use sonar systems, which operate on the principle of sound reflection to assess the spread and movement of glaciers in the Arctic region.
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MCQ 381 Mark
Modern super sonic war planes use the principle of ________ while detecting their targets.
  • echo
  • B
    SONAR
  • C
    reverberation
  • D
    none of these
Answer
Correct option: A.
echo
(a)
echo
Explanation:
Super sonic war planes use radar, employing the echo principle with radio-waves to detect and track targets by reflecting waves off them.
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MCQ 391 Mark
Bats can catch their prey by using the principle of _______________ .
  • A
    reflection of sound
  • B
    refraction of sound
  • C
    concept of echo
  • both (a) and (c)
Answer
Correct option: D.
both (a) and (c)
(d)
both (a) and (c)
Explanation :
Bats use echolocation, which involves the reflection of sound and the concept of echo to locate and catch their prey.
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MCQ 401 Mark
SONAR is a technique used to ___________ .
  • A
    detect the submarine inside sea
  • B
    determine the size of blue whale
  • C
    detect the impurities present in sea water
  • detect the depth of sea bed
Answer
Correct option: D.
detect the depth of sea bed
(d)
detect the depth of sea bed
Explanation:
SONAR (Sound Navigation And Ranging) uses sound waves to map or navigate underwater environments, including measuring the depth of the sea bed, which is one of its primary applications.
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MCQ 411 Mark
Echo occurs when the distance between source and listener is _________ .
  • A
    10 m
  • B
    17 m
  • greater than 17 m
  • D
    34 m
Answer
Correct option: C.
greater than 17 m
(c)
greater than 17 m
Explanation:
An echo is perceptible when the one-way distance between the source and listener is over 17 metre allowing sufficient time for sound to travel, reflect and be distinguished as a separate sound.
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MCQ 421 Mark
Velocity of sound is constant in ________ .
  • A
    all mediums
  • homogeneous medium
  • C
    heterogeneous medium
  • D
    vacuum
Answer
Correct option: B.
homogeneous medium
(b)
homogeneous medium
Explanation:
A homogeneous medium has uniform properties throughout its volume. Since change of frequency and wavelength does not affect the speed of sound in same medium. Therefore velocity of sound is constant in homogeneous medium.
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MCQ 431 Mark
Sound travels in the form of ___________ .
  • compression and rarefactions
  • B
    crest
  • C
    trough
  • D
    all of the above
Answer
Correct option: A.
compression and rarefactions
(a)
compression and rarefactions
Explanation:
Sound waves are longitudinal waves, which means they propagate through the compression and rarefaction of the medium they travel through.
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MCQ 441 Mark
Sound waves are waves that are produced due to __________ .
  • A
    disturbance of particles
  • B
    turbulence of particles
  • C
    vibrations of particles
  • all of the above
Answer
Correct option: D.
all of the above
(d)
all of the above
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MCQ - Physics STD 10 Questions - Vidyadip