MCQ
A mass at the end of a spring executes harmonic motion about an equilibrium position with an amplitude $A.$ Its speed as it passes through the equilibrium position is $V.$ If extended $2A$ and released, the speed of the mass passing through the equilibrium position will be
- ✓$2V$
- B$4V$
- C$\frac{V}{2}$
- D$\frac{V}{4}$