Question
A mass M1 revolves around another mass M2 in a path of radius r, what is the angular momentum associated with M1?

Answer

Angular momentum L is the product of twice the mass and aerial velocity.
$\therefore\text{L}=2\text{M}\frac{\text{dA}}{\text{dt}}=2\text{M}_1\times\frac{\pi\text{r}^2}{\text{T}}$
$=2\text{M}_1\frac{\pi\text{r}^2\text{v}}{2\pi\text{r}}$
$=\text{M}_1\text{r}\sqrt{\frac{\text{GM}_2}{\text{r}}}$
$=\text{M}_1\sqrt{\text{GM}_2\text{r}}$

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