- A40°C
- B94°C
- C93.3°C
- D30°C
Explanation:
$^\circ\text{F}=\frac{9}{5}(^\circ\text{C})+32$
$200=\frac{9}{5}(^\circ\text{C})+32$
$(^\circ\text{C})=(200-32)\times\frac{5}{9}$
$(^\circ\text{C})=93.3^\circ\text{C}$
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$\mathrm{C}_6 \mathrm{H}_6(1)+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{CO}_2(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{O}(1) \text {. }$
The standard enthalpy of combustion of $2 \mathrm{~mol}$ of benzene is - ' $x$ ' $k J$.
$\mathrm{x}=$. . . . . . . . . .
$(1)$ standard Enthalpy of formation of $1 \mathrm{~mol}$ of $\mathrm{C}_6 \mathrm{H}_6(1)$, for the reaction $6 \mathrm{C}$ (graphite) $+3 \mathrm{H}_2(\mathrm{~g}) \rightarrow \mathrm{C}_6 \mathrm{H}_n(1)$ is $48.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$.
$(2)$ Standard Enthalpy of formation of $1 \mathrm{~mol}$ of $\mathrm{CO}_2(\mathrm{~g})$, for the reaction $\mathrm{C}$ (graphite) $+\mathrm{O}_{2(\mathrm{~g})} \rightarrow \mathrm{CO}_2(\mathrm{~g})$ is $-393.5 \mathrm{~kJ} \mathrm{~mol}^{-1}$.
$(3)$ Standard and Enthalpy of formation of $1 \mathrm{~mol}$ of $\mathrm{H}_2 \mathrm{O}(1)$, for the reaction $\mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow \mathrm{H}_2 \mathrm{O}(1)$ is $-286 \mathrm{~kJ} \mathrm{~mol}^{-1}$.