b
Shear force, $F=T=m g=0.01\; kg \times 10\; m s ^{-2}=0.1\; N$
Shear stress on the fluid $=\frac{F}{A}=\frac{0.1\; N }{0.1 \;m ^{2}}$
Strain rate $=\frac{v}{l}=\frac{0.085 \;m {s}^{-1}}{0.3 \times 10^{-3}\; m }$
Coefficient of viscosity, $\eta=\frac{\text { Shear stress }}{\text { Strain rate }}$
$=\left(\frac{0.1\; N }{0.1 \;m ^{2}}\right) \times \frac{\left(0.3 \times 10^{-3}\; m \right)}{0.085\; ms ^{-1}}$
$=3.5 \times 10^{-3} Pa\cdot s$