Question
A metal ion $M^{n+}$ having $d^4$ valence electronic configuration combines with three bidentate ligands to form a complex compound. Assuming $\triangle _ {0} > \text{P}$ :
Write the electronic configuration of the valence electrons of the metal $M^{n+}$ ion in terms of $\text{t}_\text{2g} $ and $\text{e} _\text{g}$.

Answer

$\text{t}^4_\text{2g} \text{e}^0 _\text{g}$ .

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free