A metal ion M^ n+ having valence d^ 4 electronic configuration co… - Vidyadip

Question

A metal ion $M^{n+}$ having valence $d^{4}$ electronic configuration combines with three bidentate ligands to form a complex compound. Assuming $\triangle_{0} > \text{P}$: Explain orbital splitting during this complex formation.

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Answer

As $\triangle_{0} > \text{P}$ pairing will occur in the $\text{t}_\text{2g}$orbitals and eg orbitals will remain vacant.

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