Question

Answer

(i) (a): Area of the entire region $=(8 \times 5) km ^2=40 km^2$
Area of the lake $=(2 \times 2) km ^2=4 km^2$
∴ Probability that the helicopter crashed inside the lake = $\frac{4}{40}=\frac{1}{10}$
(ii) (b): Each water body is a quadrant of a circle of radius $\frac{700}{1000}$= 0.7km
Area of 3 water bodies $=\frac{3}{4} \times \frac{22}{7} \times(0.7)^2 km^2=\frac{231}{200} km^2$
∴ Probability that the helicopter crashed in one of the water bodies $=\frac{231}{200 \times 40}=\frac{231}{8000}=0.0288$
Chances of helicopter crashing in one of the water bodies = 2.88%
(iii) (c): Area of the water body nearer to the lake $=\frac{1}{4}\left(\frac{22}{7} \times 0.7 \times 0.7\right)=\frac{154}{400} km^2$
∴ Probability that the helicopter crashes in the water body nearer to the lake $=\frac{154}{400 \times 40}=\frac{77}{8000}$
(iv) (c): Area of three water bodies and lake $=\left(\frac{3}{4} \times \frac{22}{7} \times(0.7)^2+2 \times 2\right) km ^2=\frac{1031}{200} km^2$
∴ Probability that the helicopter crashes in a water body or in lake $=\frac{1031}{200 \times 40}=\frac{1031}{8000}$

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