Question
A monkey is ascending a branch with constant acceleration. If the breaking strength is 160% of the monkey's weight, what is the maximum acceleration permitted for the monkey?

Answer

Breaking strength $=\frac{160}{100}\text{mg},$ where m is the mass of the monkey. While ascending the apparent weight w = m(g + a).For safety, $\text{m(g + a)}\leq\frac{160}{100}\text{mg}$
$\therefore\ \text{a}\leq\Big(\frac{160}{100}-1\Big)\text{g,}$
$\text{i.e., a}\leq0.6\text{m/ s}^2.$

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