A motor cyclist moving with a velocity of 72 , km/hour on a flat … - Vidyadip

MCQ

A motor cyclist moving with a velocity of $72\, km/hour$ on a flat road takes a turn on the road at a point where the radius of curvature of the road is $20$ meters. The acceleration due to gravity is $10 m/sec^2$. In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

A
$\theta = {\tan ^{ - 1}}6$
✓
$\theta = {\tan ^{ - 1}}2$
C
$\theta = {\tan ^{ - 1}}25.92$
D
$\theta = {\tan ^{ - 1}}4$

✓

Answer

Correct option: B.

$\theta = {\tan ^{ - 1}}2$

b
(b)$v = 72\,km/hour = 20\,m/\sec $

$\theta = {\tan ^{ - 1}}\left( {\frac{{{v^2}}}{{rg}}} \right) = {\tan ^{ - 1}}\left( {\frac{{20 \times 20}}{{20 \times 10}}} \right) = {\tan ^{ - 1}}(2)$

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