MCQ
Two balls of same mass are projected with the same speed one vertically upwards and the other at angle $60^o$ with the vertical. The ratio of their potential energies at the highest point is :-
- A$3:2$
- B$2:1$
- ✓$4:1$
- D$4:3$
$\mathrm{K}_{1}=\frac{1}{2} \mathrm{mu}^{2}$ and
$\mathrm{K}_{2}=\frac{1}{2} \mathrm{m}\left(\mathrm{u} \cos 60^{\circ}\right)^{2}=\frac{1}{4} \times \frac{1}{2} \mathrm{mu}^{2}$
$\Rightarrow \frac{\mathrm{K}_{1}}{\mathrm{K}_{2}}=\frac{4}{1}$
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