$\mathrm{C} \theta=\mathrm{BINA} \sin 90^{\circ}$
$\mathrm{C}=\frac{\mathrm{BINA}}{\theta}=\frac{0.01 \times 10 \times 10^{-3} \times 100 \times 2 \times 10^{-4}}{0.05}$
$=4 \times 10^{-5} \mathrm{~N}-\mathrm{m} / \mathrm{rad} .$
$\mathrm{x}=4$

$STATEMENT- 2$ In the above situation, a current is induced in the ring which interacts with the horizontal component of the magnetic field to produce an average force in the upward direction.
