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4. Moving charges and magnetism — Physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 SciencePhysics4. Moving charges and magnetism1 Mark
MCQ
A moving coil galvanometer has $150$ equal divisions. Its current sensitivity is $10$ divisions per milliampere and voltage sensitivity is $2$ divisions per millivolt. In order that each division reads $1\, volt$, the resistance in $ohms$ needed to be connected in series with the coil will be
  • A
    $99995$
  • ✓
    $9995$
  • C
    ${10^3}$
  • D
    ${10^5}$
✓

Answer

Correct option: B.
$9995$
b
Voltage sensitivity $ = \frac{{{\rm{Current \,sensitivity}}}}{{{\rm{Resistance\, of \,galvanometer}}\,{\rm{G}}}}$

$ \Rightarrow $   $G = \frac{{10}}{2} = 5\,\Omega $.

Here ${i_g} = $ Full scale deflection current $ = \frac{{150}}{{10}} = 15\,mA$.

$V =$ Voltage to be measured $= 150 × 1 = 150 \,V.$

Hence $R = \frac{V}{{{i_g}}} - G = \frac{{150}}{{15 \times {{10}^{ - 3}}}} - 5 = 9995\,\Omega $.

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