A moving coil galvanometer has $48$ $turns$ and area of coil is $4 \times {10^{ - 2}}\,{m^2}.$ If the magnetic field is $0.2\, T$, then to increase the current sensitivity by $25\%$ without changing area $(A)$ and field $(B)$ the number of turns should become
  • A$24$
  • B$36$
  • C$60$
  • D$54$
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