A moving coil galvanometer has resistance $50\,\Omega $ and it indicates full deflection at $4\,mA$ current. A voltmeter is made using this galvanometer and a $5\,k\Omega $ resistance. The maximum voltage, that can be measured using this voltamenter, will be close to ......$V$
JEE MAIN 2019, Medium
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$G=50\, \Omega$
$\mathrm{S}=5000 \,\Omega$
$\mathrm{I}_{\mathrm{g}}=4 \times 10^{-3}$
$\mathrm{V}=\mathrm{i}_{g}(\mathrm{G}+\mathrm{S})$
$V=4 \times 10^{-3}(50+5000)$
$=4 \times 10^{-3}(5050)=20.2$ $volt$
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