MCQ
A number is selected at random from the numbers $\{7, 3, 9, 7, 9, 5, 7, 9, 9, 5\}$. The probability that the selected number is their average is :
  • $\frac{3}{10}$
  • B
    $\frac{7}{10}$
  • C
    $\frac{5}{10}$
  • D
    $\frac{1}{10}$

Answer

Correct option: A.
$\frac{3}{10}$
Average of given numbers $=\frac{7+3+9+7+9+5+7+9+9+5}{10}=\frac{70}{10}=7$
$($There are $3$ times $7$ in the given numbers$)$
Therefore Number of outcomes $= 3$
Number of total outcomes $= 10$
$\therefore$ Required Probability $=\frac{3}{10}$

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