A parallel plate capacitor has circular plates of $0.08\,m$ radius and $1.0 \times {10^{ - 3}}\,m$ separation. If a $P.D.$ of $100\;volt$ is applied, the charge will be
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(b) $Q = CV = \frac{{\pi {{(0.08)}^2}{\varepsilon _0}}}{{1 \times {{10}^{ - 3}}}} \times 100 = 1.8 \times {10^{ - 8}}\,C$
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