Question
If $I = 50\,kg-m^2$ , then ......... $N-m$ torque will be applied to stop it in $10\,sec$ . Its initial angular speed is $20\,rad/sec$
✓
Answer
$\tau=I \alpha=\frac{I \Delta W}{\Delta t}=\frac{50(0-20)}{10}$
$\tau=-100 \mathrm{N}-\mathrm{m}$ means
$100 \mathrm{N}-\mathrm{m}$ in opposite to angular speed.
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