$C_{i}=\frac{\varepsilon_{0} A}{d}$

$C_{i}=\frac{\varepsilon_{0}(w)}{d}$

After inserting dielectric slab

$C_{f}=C_{1}+C_{2}$

$C_{f}=\frac{K \varepsilon_{0} A_{1}}{d}+\frac{\varepsilon_{0} A_{2}}{d}$

$C_{f}=\frac{K \varepsilon_{0} W x}{d}+\frac{\varepsilon_{0} w(\ell-x)}{d}$

$C_{f}=2 C_{i} \Rightarrow \frac{K{\varepsilon_0} w x}{x}+\frac{\varepsilon_{0} w(\ell-x)}{d}=\frac{2 \varepsilon_{0}(w)}{d}$

$4 x+\ell-x=2 \ell$

$x=\frac{\ell}{3}$