
$=\mathrm{q}_{0} \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{d}}$
$=q_{0}\left(\mathrm{E}_{0} \hat{\mathrm{i}}\right)(\mathrm{a} \hat{\mathrm{i}}-\mathrm{a \hat { j }})$
$=\mathrm{q}_{0} \mathrm{E}_{\mathrm{0}} \mathrm{a}$
$STATEMENT-2$ The electrical potential of a sphere of radius $R$ with charge $\mathrm{Q}$ uniformly distributed on the surface is given by $\frac{\mathrm{Q}}{4 \pi \varepsilon_0 R}$.
Reason : For a system of positive test charge and point charge electric potential energy $=$ electric potential.




