MCQ
A parallel plate capacitor is charged. If the plates are pulled apart:
  • A
    The capacitance increases.
  • B
    The potential difference increases.
  • C
    The total charge increases.
  • D
    The charge and potential difference remain the same.

Answer

  1. The potential difference increases.

Explanation:

Capacitance of a parallel plate capacitor.

$\text{C}=ε0\text{AdC}=ε0\text{Ad}$

A parallel plate capacitor is charged (battery is disconnected) then the plates are pulled apart, the capacitance decreases while the charge remains the same.

$\because$ Potentialdifference = ChargeCapacitance∵Potentialdifference = ChargeCapacitance.

$\therefore$ potential difference increases.

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