A paramagnetic sample shows a net magnetisation of 8Am-1 when pla…

MCQ

A paramagnetic sample shows a net magnetisation of 8Am^-1 when placed in an external magnetic field of 0.6T at a temperature of 4K. When the same sample is placed in an external magnetic field of 0.2T at a temperature of 16K, the magnetisation will be

A
$\frac{32}{3}\text{Am}^{-1}$
B
$\frac{2}{3}\text{Am}^{-1}$
C
$6\text{Am}^{-1}$
D
$2.4\text{Am}^{-1}.$

✓

Answer

$\frac{2}{3}\text{Am}^{-1}.$

Solution:

From the Curie’s law explains, $\text{I}\propto\frac{\text{B}}{\text{T}}$

Here, B is magnetic field induction, I is the intensity of magnetisation and T is absolute temperature.

$\Rightarrow\ \Big(\frac{\text{I}_2}{\text{I}_1}\Big)=\Big(\frac{\text{B}_2}{\text{B}_1}\Big)\times\Big(\frac{\text{T}_1}{\text{T}_2}\Big)$

Given,

I₁ = 8 Am^-1, B₁ = 0.6T, T₁ = 4 K, B₂ = 0.2T, T₂ = 16 K, I₂ = ?

By putting values in equation …(i), we have,

$\text{I}_2=\Big(\frac{2}{3}\Big)\text{Am}^{-1}.$

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