MCQ
A particle covers $50 m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed
- A$100 m$
- B$150 m$
- ✓$200 m$
- D$250 m$
✓
Answer
Correct option: C.
$200 m$
(c) $R=\frac{u^2 \sin 2 \theta}{g}=R \propto u^2$. So if the speed of projection doubled, the range will becomes four times, i.e., $4 \times 50=200 m$
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