A particle carrying a charge equal to $100$ times the charge on an electron is rotating per second in a circular path of radius $0.8$ $metre$. The value of the magnetic field produced at the centre will be $({\mu _0} = $ permeability for vacuum)
Medium
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(b) $i = \frac{q}{t} = 100 \times e$
${B_{{\rm{centre}}}} = \frac{{{\mu _o}}}{{4\pi }}.\frac{{2\pi i}}{r} = \frac{{{\mu _o}}}{{4\pi }}.\frac{{2\pi \times 100e}}{r}$
$ = \frac{{{\mu _o} \times 200 \times 1.6 \times {{10}^{ - 19}}}}{{4 \times 0.8}} = {10^{ - 17}}{\mu _o}$
${B_{{\rm{centre}}}} = \frac{{{\mu _o}}}{{4\pi }}.\frac{{2\pi i}}{r} = \frac{{{\mu _o}}}{{4\pi }}.\frac{{2\pi \times 100e}}{r}$
$ = \frac{{{\mu _o} \times 200 \times 1.6 \times {{10}^{ - 19}}}}{{4 \times 0.8}} = {10^{ - 17}}{\mu _o}$
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