MCQ
A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
  • A
    $100$
  • B
    $150 $
  • $200 $
  • D
    $250 $

Answer

Correct option: C.
$200 $
c
(c) $R = \frac{{{u^2}\sin 2\theta }}{g} = R \propto {u^2}.$ So if the speed of projection doubled, the range will becomes four times,

i.e., $4 \times 50 = 200\,m$

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