A particle executes $SHM$ of period $1.2\, sec$ and amplitude $8\, cm.$ Find the time it takes to travel $3\,cm$ from the positive extremity of its oscillation. ..... $\sec$
Medium
Download our app for free and get started
$x=A \cos \omega t$
$\Rightarrow \quad 5 \mathrm{cm}=8 \cos \omega t$
$\Rightarrow \quad \omega t=0.9$
$\frac{2 \pi}{1.2} t=0.9$
$\Rightarrow \quad t=\frac{1.08}{2 \pi} \mathrm{s}=0.17 \mathrm{s}$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1Two particles oscillating in $SHM$ along two very close parallel path such that they have same mean position. The equation of $SHM$ of two particles are $x_1 = A\, sin\,\omega t$ and $x_2 = A\,sin(\omega t + \phi )$ respectively. If maximum distance between them is $\frac{6A}{5}$ then $\phi $ equal to ..... $^o$View Solution
- 2The displacement of a particle is given at time $t$, by:$x=A \sin (-2 \omega t)+B \sin ^2 \omega t \quad$ Then,View Solution
- 3A particle moves in $xy$ plane according to the law $x = a \sin \omega t$ and $y = a(1-\cos \omega t)$ where $a$ and $\omega$ are constants. The particle tracesView Solution
- 4A block of mass $1 \,kg$ attached to a spring is made to oscillate with an initial amplitude of $12\, cm$. After $2\, minutes$ the amplitude decreases to $6\, cm$. Determine the value of the damping constant for this motion. (take In $2=0.693$ )View Solution
- 5The scale of a spring balance reading from $0$ to $10 \,kg$ is $0.25\, m$ long. A body suspended from the balance oscillates vertically with a period of $\pi /10$ second. The mass suspended is ..... $kg$ (neglect the mass of the spring)View Solution
- 6A mass $M$ is suspended from a light spring. An additional mass m added displaces the spring further by a distance $x$. Now the combined mass will oscillate on the spring with periodView Solution
- 7Values of the acceleration $A$ of a particle moving in simple harmonic motion as a function of its displacement $x$ are given in the table below. The period of the motion isView Solution
$A (mm \,\,s^{-2}$) $16$
$8$
$0$
$- 8$
$- 16$
$x\;(mm)$
$- 4$
$- 2$
$0$
$2$
$4$
- 8The potential energy of a simple harmonic oscillator of mass $2\, kg$ in its mean position is $5\, J.$ If its total energy is $9\,J$ and its amplitude is $0.01\, m,$ its time period would beView Solution
- 9Which one of the following equations of motion represents simple harmonic motion ?View Solution
Where $k,k_0,k_1$ and $a$ are all positive
- 10$Assertion :$ The amplitude of an oscillating pendulum decreases gradually with timeView Solution
$Reason :$ The frequency of the pendulum decreases with time.