A particle executes simple harmonic motion between $x =- A$ and $x =+ A$. If time taken by particle to go from $x=0$ to $\frac{A}{2}$ is $2 s$; then time taken by particle in going from $x =\frac{ A }{2}$ to $A$ is $.........\,s$
A$3$
B$2$
C$1.5$
D$4$
JEE MAIN 2023, Medium
Download our app for free and get started
D$4$
d Let time from 0 to $A / 2$ is $t _1$
from $A / 2$ to $A$ is $t _2$ then $\omega t _1=\pi / 6$
$\omega t _2=\pi / 3$
$\frac{ t _1}{ t _2}=\frac{1}{2}$
$t _2=2 t _1=2 \times 2=4\,sec$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
A particle executes simple harmonic motion and is located at $x = a, b$ and $c$ at times $t_0, 2t_0$ and $3t_0$ respectively. The frequency of the oscillation is
A particle performs $SHM$ about $x = 0$ such that at $t = 0$ it is at $x = 0$ and moving towards positive extreme. The time taken by it to go from $x = 0$ to $x = \frac{A}{2}$ is ..... times the time taken to go from $x = \frac{A}{2}$ to $A$. The most suitable option for the blank space is
Figure shows the circular motion of a particle. The radius of the circle, the period, sense of revolution and the initial position are indicated in the figure. The simple harmonic motion of the $x-$ projection of the radius vector of the rotating particle $P$ is
An assembly of identical spring-mass systems is placed on a smooth horizontal surface as shown. At this instant, the springs are relaxed. The left mass is displaced to the/left and theiright mass is displaced to the right by same distance and released. The resulting collision is elastic. The time period of the oscillations of system is
In a sinusoidal wave, the time required for a particular point to move from maximum displacement to zero displacement is $0.170\,$second. The frequency of the wave is .... $Hz$