MCQ
A particle executes simple harmonic motion with a frequency $f$. The frequency with which its kinetic energy oscillates is
  • A
    $f/2$
  • B
    $f$
  • $2f$
  • D
    $4f$

Answer

Correct option: C.
$2f$
c
(c) Kinetic energy $K = \frac{1}{2}m{v^2} = \frac{1}{2}m{a^2}{\omega ^2}{\cos ^2}\omega \,t$

$ = \frac{1}{2}m{\omega ^2}{a^2}(1 + \cos 2\omega \,t)$

hence kinetic energy varies periodically with double the frequency of $S.H.M$. i.e. $2\omega $.

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