MCQ
A particle executes simple harmonic motion with a frequency $f$. The frequency with which its kinetic energy oscillates is
- A$f / 2$
- B$f$
- ✓$2 f$
- D$4 f$
✓
Answer
Correct option: C.
$2 f$
(c)Kinetic energy $K=\frac{1}{2} m v^2=\frac{1}{2} m a^2 \omega^2 \cos ^2 \omega t$$=\frac{1}{2} m \omega^2 a^2(1+\cos 2 \omega t)$ hence kinetic energy varies periodically with double the frequency of S.H.M. i.e. $2 \omega$.
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