MCQ
The angular speed of seconds needle in a mechanical watch is
- A$\frac{\pi}{30} rad / s$
- ✓$2 \pi rad / s$
- C$rad / s$
- D$\frac{60}{\pi} rad / s$
✓
Answer
Correct option: B.
$2 \pi rad / s$
(b) $\omega=2 \pi n=\frac{2 \pi \times 100}{60}=10.47 rad / s$
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