A particle executing simple harmonic motion with amplitude of $0.1 \,m$. At a certain instant when its displacement is $0.02 \,m$, its acceleration is $0.5 \,m/s^2$. The maximum velocity of the particle is (in $m/s$)
Easy
Download our app for free and get started
(c) Acceleration $A = {\omega ^2}y$
$ \Rightarrow \omega = \sqrt {\frac{A}{y}} = \sqrt {\frac{{0.5}}{{0.02}}} = 5$
Maximum velocity ${v_{\max }} = a\omega = 0.1 \times 5 = 0.5$
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1The resultant of two rectangular simple harmonic motions of the same frequency and unequal amplitudes but differing in phase by $\frac{\pi }{2}$ isView Solution
- 2The displacement of a particle executing periodic motion is given by :View Solution
$y = 4cos^2\,(t/2)sin\,(1000t)$
This expression may be considered to be a result of superposition of - 3The potential energy of a particle of mass $1\, kg$ in motion along the $x-$ axis is given by $U = 4\,(1 -cos\,2x)$, where $x$ is in $metres$ . The period of small oscillation (in $second$ ) isView Solution
- 4A particle is executing $SHM$ about $y=0$ along $y$-axis. Its position at an instant is given by $y=(7 \,m )$ sin( $\pi f)$. Its average velocity for a time interval $0$ to $0.5 \,s$ is ........... $m / s$View Solution
- 5A particle of mass $m$ is located in a one dimensional potential field where potential energy is given by : $V(x) = A(1 -cos\, px)$ ,View Solution
where $A$ and $p$ are constant.
The period of small oscillations of the particle is
- 6The kinetic energy of a particle executing $S.H.M.$ is $16\, J$ when it is in its mean position. If the amplitude of oscillations is $25\, cm$ and the mass of the particle is $5.12\, kg$, the time period of its oscillation isView Solution
- 7The amplitude of a particle executing $SHM$ is $3\,cm$. The displacement at which its kinetic energy will be $25 \%$ more than the potential energy is: $.............cm$.View Solution
- 8View SolutionA simple pendulum is taken from the equator to the pole. Its period
- 9A mass $m$ is suspended by means of two coiled spring which have the same length in unstretched condition as in figure. Their force constant are $k_1$ and $k_2$ respectively. When set into vertical vibrations, the period will beView Solution
- 10View SolutionIn case of a forced vibration, the resonance wave becomes very sharp when the